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[bellamy]

3.Calculer f(√2) et g(√2-2)

pour

f(x)=x(x+2)-(2x-1)(x+2)

f(x)=x²+2*x-(2*x²-x+4*x-2) g(x)=(2x-1)²-(x-3)²

f(x)=x²+2x-2x²+x-4x+2 g(x)= 4x²-4x+1-(x²-6x+9)

f(x)=-x²-x+2 g(x)=4x²-4x+1-x²+6x-9

g(x)=3x²+2x-8

f(x)=x(x+2)-(2x-1)(x+2) svp

f(x)=(x+2)*(x-(2*x-1))

f(x)=(x+2)(x-2x+1)

f(x)=(x+2)(1-x)

[Barbidoux]

f(x)=x (x + 2) - (2 x - 1) (x + 2)

f( 2)= 2 (2 + 2) - (2 + 2) (-1 + 2* 2)=- 2

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g(x)=3*x^2+2x-8

g( 2 - 2) = 3 ( 2 - 2)^2+ 2 ( 2 - 2)-8= 6-10* 2